jika f(x^2+1)=^2log x + 1, nilai f(17)+f(5)=

jawab

f(x² +1) =  ²log x + 1 , x > 0

x² +1 = 17 → x² = 16
x > 0 → x= 4

f(17) = ²log 4 + 1 = ²log 2² + 1 = 2 + 1 = 3

x²  + 1 = 5 →x² = 4
x> 0 → x = 2
f(5) = ²log 2 + 1 = 1 + 1 = 2

f(17) + f(5) = 3 + 2 = 5