tolong bantu saya mengerjakan soal diatas

jawab
9)

[tex] A \ = \left[\begin{array}{ccc}1&2\\3&4\end{array}\right] \\ det \ A = 1(4)-3(2) = -2\\ X \ = \left[\begin{array}{ccc}4&2\\2&4\end{array}\right] \\ det \ X = 4(4) - 2(2) = 12\\ Y \ = \left[\begin{array}{ccc}1&4\\3&2\end{array}\right] \\ det \ Y = 1(2) - 3(4) = -10\\ x \ = \frac{det X}{det A} \ = \frac{12}{-2} \ = -6\\ y \ = \frac{det Y}{det A} \ = \frac{-10}{-2} \ = 5 [/tex]