No 6 , 7 , 8 ,9 , 10 Tolong yaa .... saya masih bingung

6. Di siklus ada 2SO3, berarti 2 mol SO3 jadi hasil ΔH dibagi 2.
ΔHf° SO3 = -593 + (-197)
ΔHf° SO3 = -790 kJ /2
ΔHf° SO3 = -390 kJ

7. Pake hukum hess, 
ΔH = -258 + 156
ΔH = -102 kJ

8. Q = m . c . ΔT
Q = 150 . 4,2 . 4
Q = 2520 Joule
Q = 2520 x 10⁻³

nHCl = M x V
nHCl = 0,1 x 100
nHCl = 1 x 10⁻³ mol

nNaCl = M x V
nNaCl = 0,2 x 50
nNaCl = 1 x 10⁻3

ΔH=[tex]- \frac{Q}{mol} [/tex]
ΔH= -2520 x 10⁻3 / 1 x x 10⁻3
ΔH= - 2520 kJ/mol