Tolong di jawab dong ...? Semoga hidup berkah Soal bilangan logaritma

⁴log6=p,⁴log5=q
(1)(a)
⁵log4=[tex] \frac{log4}{log5} [/tex]
=[tex] \frac{ ^{4}log4 }{^{4}log5} [/tex]
=1/q
(1)(b)
[tex]^{30} log120[/tex]=[tex] \frac{log120}{log30} [/tex]
=[tex] \frac{log(6.4.5)}{log(6.5)} [/tex]
=[tex] \frac{log6+log4+log5}{log6+log5} [/tex]
=[tex] \frac{ ^{4} log6+^{4} log4+^{4} log5}{^{4} log6+^{4} log5} [/tex]
=[tex] \frac{p+1+q}{p+q} [/tex]
(2)
[tex] ^{3} log4.^{5} log9.^{4} log25 [/tex]
=[tex] ^{5} log9.^{3} log4.^{4} log25 [/tex]
=2[tex] ^{5} log3. ^{3} log4. 2^{4} log5[/tex]
=4[tex]^{5}log5 [/tex]
=4

jawabannya 4 ......
kalok gak salah