Soal tentang SPLTV Pecahan 2/x-1/y-2/z=3 1/x+2/y+4/z=4 1/x-1/y-3/z=2 mohon bantuan nya
Matematika
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Pertanyaan
Soal tentang SPLTV Pecahan
2/x-1/y-2/z=3
1/x+2/y+4/z=4
1/x-1/y-3/z=2
mohon bantuan nya
2/x-1/y-2/z=3
1/x+2/y+4/z=4
1/x-1/y-3/z=2
mohon bantuan nya
1 Jawaban
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1. Jawaban Anonyme
Sistem Persamaan Linear Tiga Variabel.
2/x - 1/y - 2/z = 3
1/x + 2/y + 4/z = 4
1/x - 1/y - 3/z = 2
Misal:
a = 1/x, b = 1/y, dan c = 1/z, sistem persamaan tersebut dapat ditulis:
2a - b - 2c = 3
a + 2b + 4c = 4
a - b - 3c = 2
2a - b - 2c = 3 | x1 | 2a - b - 2c = 3
a + 2b + 4c = 4 | x2 | 2a + 4b + 8c = 8
----------------------- -
-5b - 10c = -5 → b + 2c = 1
2a - b - 2c = 3 | x1 | 2a - b - 2c = 3
a - b - 3c = 2 | x2 | 2a - 2b - 6c = 4
-------------------- -
b + 4c = -1
b + 2c = 1
b + 4c = -1
--------------- -
-2c = 2 → c = -1
b + 2(-1) = 1 → b = 3
a - 3 - 3(-1) = 2 → a = 2
x = 1/a = 1/2
y = 1/b = 1/3
c = 1/c = -1
HP = {(1/2, 1/3, -1)}