Matematika

Pertanyaan

1. Tentukan nilai dari
a. ² log 288
b. ² log 243
2. Jika ² log 3 = a dan 5 log 3 = b
Tentukan : a. 15 log 30
b. 20 log 36
3. Tentukan x jika
a. 2 log (3x-5) = 3
b. 3 log (x²-2x) = 1
c. 5 log (x+5) = 5

1 Jawaban

  • 1. a. ²log288 = ²log(32 x 9) = 5 + ²log3²
    b. ²log243 = ²log3^5 = 5 ²log3

    2. a. 15log30 = ³log(2x3x5)/³log(3x5)
    = (1/a + 1 + 1/b)/(1 + 1/b)
    = (b + ab + a)/b x b/(b+1)
    = ( a + ab + b)/(b + 1)

    b. 20log36 = ³log(2²x3²)/³log(2²x5)
    = (2/a + 2a/a)/(2b/ab + a/ab)
    = (2+2a)/a x ab/(a+2b)
    = (2b+2ab)/(a+2b)

    3. a. 3x-5 = 8
    x = 13/3 = 4⅓

    b. x²-x = 0
    x(x-1) = 0
    x = 1

    c. x+5 = 15.625
    x = 15.620

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