2x + 3y - z = 7 3x - y + 2z = 5 2x + y + 4z = 5

Eliminasi

2x + 3y - z = 7
2x + y + 4z = 5
---------------------- (-)
2y + 5z = 2

2x + 3y - z = 7....×3
3x - y + 2z = 5....×2

6x + 9y - 3z = 21
6x - 2y + 4z = 10
------------------------ (-)
11y + 7z = 11

2y + 5z = 2....×7
11y + 7z = 11....×5

14y + 35z = 14
55y + 35z = 55
----------------------- (-)
-41y = -41
y = -41/-41
y = 1

11y + 7z = 11
11(1) + 7z = 11
7z = 11 - 11
7z = 0
z = 0/7
z = 0

2x + y + 4z = 5
2x + 1 + 4(0) = 5
2x = 5 -1
2x = 4
x = 4/2
x = 2

HP = {2,1,0}

Jadi nilai dari x, y, dan z adalah 2, 1 , dan 0

Semoga membantu :)
JANGAN LUPA KASIH 5 BINTANG