2x²-7x+3=0 menggunakan rumus abc

x = (-b +- √(b²-4ac)) / 2a
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2x²-7x+3=0
a = 2
b = -7
c = 3

x₁ = (7 + √(7² - 4(2)(3))) / 2(2)
    = (7 + √(49 - 24)) / 4
    = (7 + √25) / 4
    = (7+5) / 4
    = 12/4
    = 3

x₂ = (7 - √(7² - 4(2)(3))) / 2(2)
    = (7 - √(49 - 24)) / 4
    = (7 - √25) / 4
    = (7-5) / 4
    = 2/4
    = 1/2

2x²-7x+3 = (2x - 1) (2x - 6)
= ((2x - 1) 2 (x -3)) : 2
=(2x-1) (x-3)
2x-1=0-> x=1/2
x-3=0-> x=3
Hp={1/2,3}