Tentukan persamaan garis yang melalui titik 2,1 dan bergradien -5/7

y - y1 = m (x - x1)
y - 1 = -5/7 (x - 2)
7(y - 1) = 7(-5/7) (x-2)
7y - 7 = -35/7 (x-2)
7y - 7 = -5 (x - 2)
7y - 7 = -5x + 10
5x + 7y -7 - 10 = 0
5x + 7y -17 = 0

y-y1= m(x-x1)
y-1 = -5/7(x-2)
7(y-1)= -5(x-2)
7y-7 = -5x+10
7y = -5x+10+7
7y = -5x+17
5x+7y-17=0 (1)
5x+7y =17 (2)
7y= -5x+17
y = -5x/7+17/7
y= -5x/7+17/7. (3)