jika 3log4=a dan 3log5=b nyatakanlah 30log144 dalam a dan b tolong teman2.. =>fungsi logaritma kelas x

LogaritmA

³log 4 = a
³log 2² = a
³log 2 = a/2

³log 5 = b

••
30'log 144
= ³log 144 / ³log 30
= ³log (4² × 3²) / ³log (2 × 3 × 5)
= (³log 4² + ³log 3²) / (³log 2 + ³log 3 + ³log 5)
= (2a + 2) / (a/2 + 1 + b)
= (2a + 2) × 2/(a + 2 + 2b)
= (4a + 4)/(2 + a + 2b)