Matematika

Pertanyaan

integral tak tentu (2x -3) akar x² - 3x + 3 dx

1 Jawaban

  • InTegraL
    >> Tak Tentu

    Misal :
    u = x² - 3x + 3
    du/dx = 2x - 3
    (2x - 3) dx = du

    ∫(2x - 3)√(x² - 3x + 3) dx
    = ∫u^1/2 .du
    = 1/(3/2) . u^3/2 + C
    = 2/3 u√u + C
    = 2/3 (x² - 3x + 3)√(x² - 3x + 3) + C ✔

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