tentukan nilai x dari persamaan liner di bawah ini 2/3(x+1)=1/2x - 3

[tex]\frac{2}{3}(x+1)=\frac{1}{2}x-3 \\ \frac{2}{3}x+\frac{2}{3}=\frac{1}{2}x-3 \\ \frac{2}{3}x-\frac{1}{2}x=-3-\frac{2}{3} \\ \frac{4-3}{6}x=\frac{-9-2}{3} \\ \frac{1}{6}x=\frac{-11}{3} \\ 6\times\frac{1}{6}x=6\times \frac{-11}{3} \\ x=-22[/tex]

2/3 (x + 1) = 1/2x - 3
2/3x + 2/3 = 1/2x - 3
2/3x - 1/2x = - 3 - 2/3
4/6x - 3/6x = -3 2/3
1/6x = -11/3
x = -11/3 x 6
x = -22