Matematika

Pertanyaan

Diketahui  x-2y= 5,
2x+3z=12; y+2z=3. Nilai x+y+z=

1 Jawaban

  • x-2y=5........(i)
    2x+3z=12....(ii)
    y+2z=3........(iii)
    x+y+z=...?
    x-2(3-2z)=5
    x-6+4z=5
    x+4z=11.....(iv)

    (i) dan (iv)

    2x+3z=12
    2(11-4z)+3z=12
    22-8z+3z=12
    -5z=-10
    z=2

    2x+6=12
    x=3

    y+4=3
    y=-1

    x+y+z=3-1+2=4

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