persamaan garis yg melalui titik (4,1) dan (6,-2)

rumus persamaan garis untuk 2 titik 

(y-y1)/(y2-y1) = (x-x1)/(x2-x1)
(y-1)/(-2-1) = (x-4)/(6-4)
(y-1)/-3 = (x-4)/2
2(y-1) = -3(x-4)
2y - 2 = -3x + 12
2y = -3x + 14