berapa isi dari 14 log 56, jika 2 log 3 = a & 3 log 7 = b

jawab

²log 3 = a
³ log 7 = b
(²log 3 . ³log 7) = a b → ²log 7 = ab

¹⁴log 56 = ²log 56 / ²log 14
= (²log 8 + ²log 7) / (²log 2 + ²log 7)
= (²log 2³ + ab ) / (1 + ab)
= (3 + ab )/ (a + ab)