Matematika

Pertanyaan

jika 6^x-2y = 1/216 an 4^x-y = 256, aka x+y = ...

1 Jawaban

  • jawab

    6^(x - 2y)  = 1/216 = 6^(-3)
    x - 2y = - 3

    4^(x-y) = 256 = 4^4
    x - y = 4

    x - 2y = -3
    x - y = 4  || (-)
    -y = - 7
    y = 7

    x - y = 4
    x = y + 4
    x = 7+4
    x = 11

    x + y  = 11 + 7
    x + y  = 18

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