minta tolong kakak no. 1&2
Matematika
ekaseptiawati
Pertanyaan
minta tolong kakak no. 1&2
1 Jawaban
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1. Jawaban iinfasha94
[tex] \lim_{x \to \ 2} \frac{ x^{4} -8x}{ x^{2} -x-2} [/tex]
[tex] \lim_{x \to \ 2} \frac{ x( x^{3}-8 )}{(x-2)(x+1)} [/tex]
[tex] \lim_{x \to \ 2} \frac{x(x-2)( x^{2} +2x+4)}{(x-2)(x+1)} [/tex]
[tex] \lim_{x \to \ 2} \frac{x( x^{2} +2x+4)}{(x+1)} [/tex]
= [tex] \frac{2( 2 ^{2} +2.2+4)}{2+1} [/tex]
= [tex] \frac{2(4+4+4)}{3} [/tex]
=[tex] \frac{24}{3} [/tex]
=8
Jawaban A
No. 2
[tex] \lim_{x \to \ 0} \frac{ x^{3}-2 x^{2} }{ x^{2} -3x} + \frac{ x^{2} +x}{ x^{2} -x} [/tex]
[tex] \lim_{x \to \ 0} \frac{ x^{2} (x-2)}{x(x-3)} + \frac{x(x+1)}{x(x-1)} [/tex]
[tex] \lim_{x \to \ 0} \frac{ x (x-2)}{(x-3)} + \frac{(x+1)}{(x-1)} [/tex]
=[tex] \frac{0(0-2)}{0-3} [/tex] + [tex] \frac{0+1}{0-1} [/tex]
=0 +[tex] \frac{1}{-1} [/tex]
=-1
Jawaban B