Matematika

Pertanyaan

tolong bantu soal ini, beserta caranya , makasih
tolong bantu soal ini, beserta caranya , makasih

1 Jawaban

  • jawab
    "
    ²³log 2^(3/2) .(x) = 1/3

    2.^(3/2) (x) = (23)^(1/3)
    {(2)^3/2  (x)}³  = { 23^(1/3)}³
    (2)^(9/2) (x)^3 = 23
    x^3 = 23/ (2^4 √2)
    x³ = 23/16√2
    x³  = (23√2) /(32)

    x = ∛ [ 23/32 √2]