Matematika

Pertanyaan

no 4 sampai 5 besok dikumpulkan tolong ya
no 4 sampai 5 besok dikumpulkan tolong ya

2 Jawaban

  • 4) A. 3 kali 2 = 6 : 2 = ...............
         B. d1 : d2 dikali 6 ............
         c.
  • 4. B. L1 = phi × r^2 ÷ 2

    = 3,14 × 6^2 ÷ 2

    = 3,14 × 36 ÷ 2

    = 3,14 × 18

    = 56,52 cm^2


    L2 = 1/2 × A × T

    = 1/2 × 6 × 7

    = 1 × 3 × 7

    = 21 cm^2


    LG = 56,52 + 21

    = 77,52 cm^2



    D. L = phi × r^2 ÷ 2

    = 22/7 × 7^2 ÷ 2

    = 22/7 × 49 ÷ 2

    = 22 × 7 ÷ 2

    = 11 × 7

    = 77 cm^2



    5. A. L = phi × r^2

    616 = 22/7 × r^2

    r^2 = 616 ÷ 22/7

    r^2 = 616 × 7/22

    r^2 = 28 × 7

    r^2 = 196 (diakarkan pangkat 2)

    r^2 = 14 cm


    B. K = 2 × phi × r

    = 2 × 22/7 × 14

    = 2 × 22 × 2

    = 88 cm