Jika ^27log 2= p, menyatakan logaritma berikut dalam p! A.^2log 3 b. ^3log 32 c. ^24log 648

LogaRitMa

27'log 2 = p
3³'log 2 = p
3'log 2 = 3p

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2'log 3 = 1/(3p)

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3'log 32
= 3'log 2^5
= 5 × 3'log 2
= 15p

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24'log 648
= ³log 648 / ³log 24
= ³log (2³ . 3⁴) / ³log (3 . 2³)
= (³log 2³ + ³log 3⁴ ) / (³log 3 + ³log 2³)
= (3 . 3p + 4) / (1 + 3 . 3p)
= (4 + 9p) / (1 + 9p)